Bug in Julian to Gregorian Date Conversion

There is a bug in this Julian to Gregorian Date conversion routine. It converts today 2003:90 to March 31, 2003 to April 00, 2003. Routine follows. Also show that your new routine correctly converts all days of the year. public int[] julianToGregorianDate(int Year, int Day) { double xjdate; double xjd; double z; double fday; double alpha; double a, b; int ic, id, ie; int day, month, iyear; xjd=(4715+Year)*365.25+Day-1110; z = (int)(double)(xjd + 0.5); fday = xjd + 0.5 - z; if (fday < 0.0) { fday = fday + 1.0; z = z - 1; } if (z < 2299161) a = z; else { alpha = ((double)(z - 1867216.25) / 36524.25); a = z + 1.0 + alpha - (int)(double)(alpha / 4.0); } b = a + 1524.0; ic = (int)(double)((b - 122.1) / 365.25); id = (int)(double)(365.25 * ic); ie = (int)(double)((b - id) / 30.6001); day = (int)(double)(b - id - (int)(double) 30.6001 * ie)); if (ie < 14) month = ie - 1; else month = ie - 13; if (month > 2) iyear = ic - 4716; else iyear = Year; int[] dateP; dateP = new int[3]; dateP[0] =iyear; dateP[1] =month; dateP[2] = day; return dateP; ## Deliverables 1) Complete and fully-functional working program(s) in executable form as well as complete source code of all work done. 2) Complete ownership and distribution copyrights to all work purchased. ## Platform Windows, Linux